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Mathematics
Problem
Suppose
f
f
f
and
g
g
g
are differentiable on
R
\mathbb R
R
with
f
(
0
)
=
g
(
0
)
f(0)=g(0)
f
(
0
)
=
g
(
0
)
and
(
f
−
g
)
′
(
x
)
>
0
(f-g)'(x)>0
(
f
−
g
)
′
(
x
)
>
0
for all
x
≠
0
x\ne0
x
=
0
. How many real solutions can the equation
f
(
x
)
=
g
(
x
)
f(x)=g(x)
f
(
x
)
=
g
(
x
)
have? Justify briefly.
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