Mathematics

Mathematics

Problem

Consider the function h(x)=−2x−3h(x)=\dfrac{-2}{x-3}. a. (i) Find the domain and the range of hh. b. (ii) Calculate lim⁡x→3+h(x)\displaystyle \lim_{x\to3^+} h(x) and lim⁡x→3−h(x)\displaystyle \lim_{x\to3^-} h(x) as well as lim⁡x→+∞h(x)\displaystyle \lim_{x\to+\infty} h(x) and lim⁡x→−∞h(x)\displaystyle \lim_{x\to-\infty} h(x). c. (iii) Determine the coordinates of the points on the graph for which h(x)=1h(x)=1 and h(x)=−1h(x)=-1. d. (iv) Sketch the graph of hh indicating the branch in each quadrant and the behaviour of the curve near x=3x=3 and for large values of ∣x∣|x|. Explain how the negative sign in the numerator affects the placement of the branches compared with 2x−3\dfrac{2}{x-3}.

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