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Mathematics
Mathematics
Problem
Let
A
=
{
(
x
,
y
)
∈
R
2
:
y
≥
0
,
2
x
≤
y
≤
4
−
(
x
−
1
)
2
}
A = \{(x, y) \in \mathbb{R}^2 : y \ge 0, 2x \le y \le \sqrt{4 - (x-1)^2}\}
A
=
{(
x
,
y
)
∈
R
2
:
y
≥
0
,
2
x
≤
y
≤
4
−
(
x
−
1
)
2
}
and
B
=
{
(
x
,
y
)
∈
R
×
R
:
0
≤
y
≤
min
{
2
x
,
4
−
(
x
−
1
)
2
}
}
B = \{(x, y) \in \mathbb{R} \times \mathbb{R} : 0 \le y \le \min\{2x, \sqrt{4 - (x-1)^2}\}\}
B
=
{(
x
,
y
)
∈
R
×
R
:
0
≤
y
≤
min
{
2
x
,
4
−
(
x
−
1
)
2
}}
Then the ratio of the area of A to the area of B is (A)
π
−
1
π
+
1
\frac{\pi - 1}{\pi + 1}
π
+
1
π
−
1
(B)
π
π
−
1
\frac{\pi}{\pi - 1}
π
−
1
π
(C)
π
π
+
1
\frac{\pi}{\pi + 1}
π
+
1
π
(D)
π
+
1
π
−
1
\frac{\pi + 1}{\pi - 1}
π
−
1
π
+
1
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