Mathematics

Mathematics

Problem

Let A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2}A = \{(x, y) \in \mathbb{R}^2 : y \ge 0, 2x \le y \le \sqrt{4 - (x-1)^2}\} and B={(x,y)∈R×R:0≤y≤min⁡{2x,4−(x−1)2}}B = \{(x, y) \in \mathbb{R} \times \mathbb{R} : 0 \le y \le \min\{2x, \sqrt{4 - (x-1)^2}\}\} Then the ratio of the area of A to the area of B is (A) π−1π+1\frac{\pi - 1}{\pi + 1} (B) ππ−1\frac{\pi}{\pi - 1} (C) ππ+1\frac{\pi}{\pi + 1} (D) π+1π−1\frac{\pi + 1}{\pi - 1}

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