Problem

Problem

If in △ABC\triangle ABC , tan⁡A+tan⁡B+tan⁡C=6\tan A + \tan B + \tan C = 6 and tan⁡Atan⁡B=2\tan A \tan B = 2 , then sin⁡2A:sin⁡2B:sin⁡2C\sin^2 A : \sin^2 B : \sin^2 C is a. 8 : 9 : 5 b. 8 : 5 : 9 c. 5 : 9 : 5 d. 5 : 8 : 5

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