Solve tan⁡−1(x+1x−1)+tan⁡−1(x−1x)=tan⁡−1(−7)\tan^{-1}\left(\frac{x+1}{x-1}\right) + \tan^{-1}\left(\frac{x-1}{x}\right) = \tan^{-1}(-7)

Problem

Solve tan⁡−1(x+1x−1)+tan⁡−1(x−1x)=tan⁡−1(−7)\tan^{-1}\left(\frac{x+1}{x-1}\right) + \tan^{-1}\left(\frac{x-1}{x}\right) = \tan^{-1}(-7)

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