Mathematics

Mathematics

Problem

For t>0t>0, the position (in meters) of a particle is given by s(t)=2t53−5t23s(t)=2t^{\tfrac{5}{3}}-5t^{\tfrac{2}{3}}. At what time is the particle’s acceleration equal to zero? a) 1 s1\,\text{s} b) 12 s\dfrac12\,\text{s} c) Acceleration is never zero for t>0t>0 d) 14 s\dfrac14\,\text{s}

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