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Problem
Problem
Let
α
,
β
∈
R
\alpha, \beta \in \mathbb{R}
α
,
β
∈
R
be such that
lim
x
→
0
x
2
sin
(
β
x
)
α
x
−
sin
x
=
1
\lim_{x \to 0} \frac{x^2 \sin(\beta x)}{\alpha x - \sin x} = 1
lim
x
→
0
α
x
−
s
i
n
x
x
2
s
i
n
(
β
x
)
=
1
. Then,
6
(
α
+
β
)
6(\alpha + \beta)
6
(
α
+
β
)
equals
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