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Mathematics
Mathematics
Problem
Find the limiting points of the circles
(
x
2
+
y
2
+
2
g
x
+
c
)
+
λ
(
x
2
+
y
2
+
2
f
y
+
d
)
=
0
(x^2 + y^2 + 2gx + c) + \lambda (x^2 + y^2 + 2fy + d) = 0
(
x
2
+
y
2
+
2
g
x
+
c
)
+
λ
(
x
2
+
y
2
+
2
f
y
+
d
)
=
0
and show that the square of the distance between them is
(
c
−
d
)
2
−
4
f
2
g
2
+
4
c
f
2
+
4
d
g
2
f
2
+
g
2
\frac{(c-d)^2 - 4f^2g^2 + 4cf^2 + 4dg^2}{f^2 + g^2}
f
2
+
g
2
(
c
−
d
)
2
−
4
f
2
g
2
+
4
c
f
2
+
4
d
g
2
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