If $\frac{1^3 + 2^3 + 3^3 + \dots \text{upto } n \text{ terms}}{1 \cdot 3 + 2 \cdot 5 + 3 \cdot 7 + \dots \text{upto } n \text{ terms}} = \frac{9}{5}$ …

Mathematics

Problem

\frac{1^3 + 2^3 + 3^3 + \dots \text{upto } n \text{ terms}}{1 \cdot 3 + 2 \cdot 5 + 3 \cdot 7 + \dots \text{upto } n \text{ terms}} = \frac{9}{5}

, then the value of

n

is a