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Mathematics
Mathematics
Problem
If
f
(
x
)
=
x
−
1
f(x) = x - 1
f
(
x
)
=
x
−
1
and
g
(
x
)
=
∣
f
(
∣
x
∣
)
−
2
∣
g(x) = |f(|x|) - 2|
g
(
x
)
=
∣
f
(
∣
x
∣
)
−
2∣
, then the area bounded by
y
=
g
(
x
)
y = g(x)
y
=
g
(
x
)
and the curve
x
2
−
4
y
+
8
=
0
x^2 - 4y + 8 = 0
x
2
−
4
y
+
8
=
0
is equal to a.
4
3
(
4
2
−
5
)
\frac{4}{3}(4\sqrt{2} - 5)
3
4
(
4
2
−
5
)
b.
8
3
(
4
2
−
3
)
\frac{8}{3}(4\sqrt{2} - 3)
3
8
(
4
2
−
3
)
c.
4
3
(
4
2
−
3
)
\frac{4}{3}(4\sqrt{2} - 3)
3
4
(
4
2
−
3
)
d.
8
3
(
4
2
−
5
)
\frac{8}{3}(4\sqrt{2} - 5)
3
8
(
4
2
−
5
)
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