Problem

A nucleus

X

initially at rest, undergoes alpha decay according to the equation

{}_{Z}^{232}X \to {}_{90}^{A}Y + \alpha

What fraction of the total energy released in the decay will be the kinetic energy of the alpha particle? a.

\frac{90}{92}

\frac{228}{232}

\sqrt{\frac{228}{232}}

\frac{1}{2}