Blundell Thermal Physics · Problem 5.4

The Maxwell–Boltzmann distribution

Physics — Statistical Mechanics · maxwell-boltzmann-mean-speeds

Problem

A Maxwell--Boltzmann distribution implies that a given molecule (mass mm) will have a speed between vv and v+dvv+\mathrm{d}v with probability equal to f(v) dvf(v)\,\mathrm{d}v where f(v)∝v2e−mv2/2kBT,f(v) \propto v^2 \mathrm{e}^{-mv^2/2k_\mathrm{B}T}, and the proportionality sign is used because a normalization constant has been omitted. (You can correct for this by dividing any averages you work out by ∫0∞f(v) dv\int_0^\infty f(v)\,\mathrm{d}v.) For this distribution, calculate the mean speed ⟨v⟩\langle v \rangle and the mean inverse speed ⟨1/v⟩\langle 1/v \rangle. Show that ⟨v⟩⟨1/v⟩=4π.\langle v \rangle \langle 1/v \rangle = \frac{4}{\pi}.

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