A Maxwell--Boltzmann distribution implies that a given molecule (mass m) will have a speed between v and v+dv with probability equal to f(v)dv where
f(v)∝v2e−mv2/2kBT,
and the proportionality sign is used because a normalization constant has been omitted. (You can correct for this by dividing any averages you work out by ∫0∞f(v)dv.) For this distribution, calculate the mean speed ⟨v⟩ and the mean inverse speed ⟨1/v⟩. Show that
⟨v⟩⟨1/v⟩=π4.