If A−1=[sin⁡2α000sin⁡2β000sin⁡2γ]A^{-1} = \begin{bmatrix} \sin^2 \alpha & 0 & 0 \\ 0 & \sin^2 \beta & 0 \\ 0 & 0 & \sin^2 \gamma \end{bmatrix}…

Problem

If A−1=[sin⁡2α000sin⁡2β000sin⁡2γ]A^{-1} = \begin{bmatrix} \sin^2 \alpha & 0 & 0 \\ 0 & \sin^2 \beta & 0 \\ 0 & 0 & \sin^2 \gamma \end{bmatrix} and B−1=[cos⁡2α000cos⁡2β000cos⁡2γ]B^{-1} = \begin{bmatrix} \cos^2 \alpha & 0 & 0 \\ 0 & \cos^2 \beta & 0 \\ 0 & 0 & \cos^2 \gamma \end{bmatrix} where α,β,γ\alpha, \beta, \gamma are any real numbers and C=(A−5+B−5)+5A−1B−1(A−3+B−3)+10A−2B−2(A−1+B−1)C = (A^{-5} + B^{-5}) + 5A^{-1}B^{-1}(A^{-3} + B^{-3}) + 10A^{-2}B^{-2}(A^{-1} + B^{-1}) then find ∣C∣|C| . (a) 0 (b) 1 (c) 2 (d) 3

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