Mathematics

Mathematics

Problem

A continuous function hh intersects the xx-axis at x=−2x=-2, x=1x=1, and x=4x=4. A student plans to compute the area of the region in the first quadrant bounded by hh and the xx-axis by evaluating ∫−24h(x) dx\displaystyle\int_{-2}^{4} h(x)\,dx. Which of the following best explains why this choice of limits may yield an incorrect value for the desired area? a) Because hh changes concavity on [−2,4][-2,4], one integral cannot represent the area of regions with different curvature. b) Since the region lies entirely in the first quadrant, the lower limit must be x=0x=0, not x=−2x=-2. A single integral from 00 to 44 would suffice. c) Portions of [−2,0][-2,0] lie below the xx-axis, so the integral over that interval would subtract, rather than add, area. d) The integral from −2-2 to 44 double-counts the area on [1,4][1,4], leading to an over-estimate.

Browse the problem library