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Problem
Problem
If the electron in hydrogen orbit jumps from third orbit to second orbit, the wavelength of the emitted radiation is given by a.
λ
=
R
6
\lambda = \frac{R}{6}
λ
=
6
R
b.
λ
=
5
R
\lambda = \frac{5}{R}
λ
=
R
5
c.
λ
=
36
5
R
\lambda = \frac{36}{5R}
λ
=
5
R
36
d.
λ
=
5
R
36
\lambda = \frac{5R}{36}
λ
=
36
5
R
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