Problem

Problem

If the electron in hydrogen orbit jumps from third orbit to second orbit, the wavelength of the emitted radiation is given by a. λ=R6\lambda = \frac{R}{6} b. λ=5R\lambda = \frac{5}{R} c. λ=365R\lambda = \frac{36}{5R} d. λ=5R36\lambda = \frac{5R}{36}

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