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Chemistry
Chemistry
Problem
The solubility of silver bromide in hypo solution is due to the formation of : a.
Ag
2
SO
3
\text{Ag}_2\text{SO}_3
Ag
2
SO
3
b.
Ag
2
S
2
O
3
\text{Ag}_2\text{S}_2\text{O}_3
Ag
2
S
2
O
3
c.
[
Ag
(
S
2
O
3
)
]
−
[\text{Ag}(\text{S}_2\text{O}_3)]^-
[
Ag
(
S
2
O
3
)
]
−
d.
[
Ag
(
S
2
O
3
)
2
]
3
−
[\text{Ag}(\text{S}_2\text{O}_3)_2]^{3-}
[
Ag
(
S
2
O
3
)
2
]
3
−
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