Physics

Physics · electromagnetism

Problem

a) Show that the radial deviation of the electrons from the injection radius is finite. Given constants: A beam of electrons emitted by a point source P\mathrm{P} enters the magnetic field B⃗\vec{B} of a toroidal coil (toroid) in the direction of the lines of force. The angle of the aperture of the beam 2⋅α02 \cdot \alpha_{0} is assumed to be small (2⋅α0<<1)\left(2 \cdot \alpha_{0}<<1\right). The injection of the electrons occurs on the mean radius R\mathrm{R} of the toroid with acceleration voltage V0\mathrm{V}_{0}. Neglect any interaction between the electrons. The magnitude of B⃗,B\vec{B}, B, is assumed to be constant. <image_1> Data: em=1.76⋅1011C⋅kg−1;V0=3kV;R=50 mm\frac{\mathrm{e}}{\mathrm{m}}=1.76 \cdot 10^{11} \mathrm{C} \cdot \mathrm{kg}^{-1} ; \quad \mathrm{V}_{0}=3 \mathrm{kV} ; \quad \mathrm{R}=50 \mathrm{~mm} Context question: 1. To guide the electron in the toroidal field a homogeneous magnetic deflection field B⃗1\vec{B}_{1} is required. Calculate B⃗1\vec{B}_{1} for an electron moving on a circular orbit of radius RR in the torus. Context answer: 1.48⋅10−21.48 \cdot 10^{-2} Context question: 2. Determine the value of B⃗\vec{B} which gives four focussing points separated by π/2\pi / 2 as indicated in the diagram. Note: When considering the electron paths you may disregard the curvature of the magnetic field. Context answer: 0.37⋅10−20.37 \cdot 10^{-2} Extra Supplementary Reading Materials: 3. The electron beam cannot stay in the toroid without a deflection field B⃗1\vec{B}_{1}, but will leave it with a systematic motion (drift) perpendicular to the plane of the toroid. Note: The angle of aperture of the electron beam can be neglected. Use the laws of conservation of energy and of angular momentum.

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