Mathematics

Problem

Triangles

PQR

and

RPS

are drawn such that

PQ = RS = 4\,\text{cm}

PR

is common, and

\angle QPR = \angle SRP = 70^{\circ}

. If

QR = 3x - 2\,\text{cm}

and

PS = x + 6\,\text{cm}

, the value of

x

is a)

2

8

4

6