Problem

Sulfur hexafluoride is synthesized by burning sulfur in fluorine gas. The reaction is described by the equation:

\text{S(s)} + 3\text{F}_2\text{(g)} \rightarrow \text{SF}_6\text{(g)}

4 moles of sulfur (atoms) are added to 20 moles of fluorine (molecules). Deduce which will be the limiting reactant.