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Chemistry
Chemistry
Problem
0.2 mole of
NH
4
Cl
\text{NH}_4\text{Cl}
NH
4
Cl
are introduced into an empty container of 10 litre and heated to
327
∘
C
327^\circ\text{C}
32
7
∘
C
to attain equilibrium as:
NH
4
Cl
(
s
)
⇌
NH
3
(
g
)
+
HCl
(
g
)
\text{NH}_4\text{Cl}(s) \rightleftharpoons \text{NH}_3(g) + \text{HCl}(g)
NH
4
Cl
(
s
)
⇌
NH
3
(
g
)
+
HCl
(
g
)
;
K
p
=
0.36
atm
2
K_p = 0.36\,\text{atm}^2
K
p
=
0.36
atm
2
. The quantity of solid
NH
4
Cl
\text{NH}_4\text{Cl}
NH
4
Cl
left is: a. 0.02 mol b. 0.078 mol c. 0.095 mol d. 0.035 mol
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