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Problem
Problem
Show that
(
1
r
1
+
1
r
2
)
(
1
r
2
+
1
r
3
)
(
1
r
3
+
1
r
1
)
=
64
R
3
a
2
b
2
c
2
\left(\frac{1}{r_1} + \frac{1}{r_2}\right)\left(\frac{1}{r_2} + \frac{1}{r_3}\right)\left(\frac{1}{r_3} + \frac{1}{r_1}\right) = \frac{64R^3}{a^2 b^2 c^2}
(
r
1
1
+
r
2
1
)
(
r
2
1
+
r
3
1
)
(
r
3
1
+
r
1
1
)
=
a
2
b
2
c
2
64
R
3
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