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Mathematics
Problem
If the general solution of the differential equation
y
′
=
y
x
+
Φ
(
x
y
)
y' = \frac{y}{x} + \Phi\left(\frac{x}{y}\right)
y
′
=
x
y
+
Φ
(
y
x
)
, for some function
Φ
\Phi
Φ
, is given by
y
ln
∣
c
x
∣
=
x
y \ln |cx| = x
y
ln
∣
c
x
∣
=
x
, where
c
c
c
is an arbitrary constant, then
Φ
(
2
)
\Phi(2)
Φ
(
2
)
is equal to : [JEE-MAIN ONLINE-2014] (1) 4 (2)
−
4
-4
−
4
(3)
1
4
\frac{1}{4}
4
1
(4)
−
1
4
-\frac{1}{4}
−
4
1
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