Mathematics

Mathematics

Problem

If the general solution of the differential equation y′=yx+Φ(xy)y' = \frac{y}{x} + \Phi\left(\frac{x}{y}\right) , for some function Φ\Phi , is given by yln⁡∣cx∣=xy \ln |cx| = x , where cc is an arbitrary constant, then Φ(2)\Phi(2) is equal to : [JEE-MAIN ONLINE-2014] (1) 4 (2) −4-4 (3) 14\frac{1}{4} (4) −14-\frac{1}{4}

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