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Mathematics
Mathematics
Problem
The circle
r
=
2
r=2
r
=
2
and the limaçon
r
=
4
cos
θ
r=4\cos\theta
r
=
4
cos
θ
intersect at
θ
=
±
π
3
\theta=\pm\tfrac{\pi}{3}
θ
=
±
3
π
. Determine the exact area of the region that lies inside
r
=
4
cos
θ
r=4\cos\theta
r
=
4
cos
θ
and outside
r
=
2
r=2
r
=
2
. a)
8
π
3
+
4
3
\displaystyle \frac{8\pi}{3}+4\sqrt{3}
3
8
π
+
4
3
b)
2
π
3
+
3
\displaystyle \frac{2\pi}{3}+\sqrt{3}
3
2
π
+
3
c)
4
π
3
+
2
3
\displaystyle \frac{4\pi}{3}+2\sqrt{3}
3
4
π
+
2
3
d)
4
π
3
−
2
3
\displaystyle \frac{4\pi}{3}-2\sqrt{3}
3
4
π
−
2
3
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