Chemistry

Chemistry

Problem

The lowest-energy orbit of the electron in a lithium ion Li2+\text{Li}^{2+} (nuclear charge +3e+3e) can be expressed in terms of the Bohr radius a0=5.29×10−11 ma_{0}=5.29\times10^{-11}\,\text{m}. What is the radius of this orbit? a) 5.3×10−11 m5.3\times10^{-11}\,\text{m} b) 5.9×10−12 m5.9\times10^{-12}\,\text{m} c) 1.8×10−11 m1.8\times10^{-11}\,\text{m} d) 7.1×10−11 m7.1\times10^{-11}\,\text{m}

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