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Mathematics
Mathematics
Problem
Given
P
(
Y
)
=
0.35
P(Y) = 0.35
P
(
Y
)
=
0.35
and
P
(
X
∪
Y
)
=
0.8
P(X \cup Y) = 0.8
P
(
X
∪
Y
)
=
0.8
, and that
X
X
X
and
Y
Y
Y
are mutually exclusive events, find: a.
P
(
X
∩
Y
)
P(X \cap Y)
P
(
X
∩
Y
)
b.
P
(
X
)
P(X)
P
(
X
)
c.
P
(
X
or
Y
but not both
)
P(X \text{ or } Y \text{ but not both})
P
(
X
or
Y
but not both
)
.
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