Physics

Physics

Problem

A projectile is launched at an angle α\alpha with the horizontal with a velocity 20 ms−120 \text{ ms}^{-1}. After 10 s, its inclination with horizontal is β\beta. The value of tan⁡β\tan \beta will be: (g=10 ms−2g = 10 \text{ ms}^{-2}) [Main June 27, 2022 (I)] (a) tan⁡α+5sec⁡α\tan \alpha + 5 \sec \alpha (b) tan⁡α−5sec⁡α\tan \alpha - 5 \sec \alpha (c) 2tan⁡α−5sec⁡α2 \tan \alpha - 5 \sec \alpha (d) 2tan⁡α+5sec⁡α2 \tan \alpha + 5 \sec \alpha

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