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Mathematics
Problem
A curve passing through (2, 3) and satisfying the differential equation
∫
0
x
t
y
(
t
)
d
t
=
x
2
y
(
x
)
,
(
x
>
0
)
\int_{0}^{x} ty(t)dt = x^2y(x), (x > 0)
∫
0
x
t
y
(
t
)
d
t
=
x
2
y
(
x
)
,
(
x
>
0
)
is - (A)
x
2
+
y
2
=
13
x^2 + y^2 = 13
x
2
+
y
2
=
13
(B)
y
2
=
9
2
x
y^2 = \frac{9}{2}x
y
2
=
2
9
x
(C)
x
2
8
+
y
2
18
=
1
\frac{x^2}{8} + \frac{y^2}{18} = 1
8
x
2
+
18
y
2
=
1
(D)
x
y
=
6
xy = 6
x
y
=
6
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