At 298 K the value of log10K for the gas-phase reaction X2(g) ⇌ 2X(g) is –0.75. Which statement about log10K for the reverse reaction 2X(g) ⇌ X2(g) is most accurate?
a) It is −0.75 because reversing the reaction does not change log10K.
b) It is +1.50 because reversing and taking into account the stoichiometric factor of 2 doubles and changes the sign of log10K.
c) It is +0.75 because taking the reciprocal of K makes log10K change sign.
d) It is 0 because the reverse reaction is at equilibrium when K=1.