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Problem
When excess aqueous ammonia is added to a solution of hydrated nickel ions, the blue hexaammine complex ion is formed from the hexaaqua ion.
[
Ni
(
H
2
O
)
6
]
2
+
(
aq
)
[\text{Ni}(\text{H}_2\text{O})_6]^{2+}(\text{aq})
[
Ni
(
H
2
O
)
6
]
2
+
(
aq
)
+
+
+
6
NH
3
(
aq
)
6\text{NH}_3(\text{aq})
6
NH
3
(
aq
)
→
\rightarrow
→
[
Ni
(
NH
3
)
6
]
2
+
(
aq
)
[\text{Ni}(\text{NH}_3)_6]^{2+}(\text{aq})
[
Ni
(
NH
3
)
6
]
2
+
(
aq
)
+
+
+
6
H
2
O
(
l
)
6\text{H}_2\text{O}(\text{l})
6
H
2
O
(
l
)
green
\text{green}
green
blue
\text{blue}
blue
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