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Mathematics
Mathematics
Problem
Find the equation of the plane containing the line
x
−
1
3
=
y
+
6
4
=
z
+
1
2
\frac{x-1}{3} = \frac{y+6}{4} = \frac{z+1}{2}
3
x
−
1
=
4
y
+
6
=
2
z
+
1
and parallel to the line
x
−
4
2
=
y
−
1
−
3
=
z
+
3
5
.
\frac{x-4}{2} = \frac{y-1}{-3} = \frac{z+3}{5}.
2
x
−
4
=
−
3
y
−
1
=
5
z
+
3
.
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