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Problem
The apparatus shows the use of electrolysis to split water into hydrogen and oxygen in the following reaction:
H
2
O
(
l
)
→
2
H
2
(
g
)
+
O
2
(
g
)
\text{H}_2\text{O}(\text{l}) \rightarrow 2 \text{H}_2(\text{g}) + \text{O}_2(\text{g})
H
2
O
(
l
)
→
2
H
2
(
g
)
+
O
2
(
g
)
. How can you explain the observed difference in volumes of the two gases produced?
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