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Chemistry
Chemistry
Problem
The value of
n
n
n
in the reaction:
Cr
2
O
7
2
−
+
n
e
+
14
H
+
⟶
2
Cr
3
+
+
7
H
2
O
\text{Cr}_2\text{O}_7^{2-} + n\text{e} + 14\text{H}^+ \longrightarrow 2\text{Cr}^{3+} + 7\text{H}_2\text{O}
Cr
2
O
7
2
−
+
n
e
+
14
H
+
⟶
2
Cr
3
+
+
7
H
2
O
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