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Problem
Problem
Show that
x
(
1
+
x
)
<
log
(
1
+
x
)
<
x
\frac{x}{(1+x)} < \log(1+x) < x
(
1
+
x
)
x
<
lo
g
(
1
+
x
)
<
x
for
x
>
0
x > 0
x
>
0
.
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