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Mathematics
Mathematics
Problem
Evaluate
∑
k
=
3
12
(
2
k
−
1
)
\displaystyle \sum_{k=3}^{12} (2k - 1)
k
=
3
∑
12
(
2
k
−
1
)
. a)
143
143
143
b)
130
130
130
c)
140
140
140
d)
180
180
180
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