JEE Advanced 2021 Paper 1 Chemistry Q8

Chemistry · Free Energy & Chemical Equilibrium

Problem

For the reaction, X(s) ⇌ Y(s) + Z(g), the plot of ln(pZ/p°) versus 10⁴/T is given below (in solid line), where pZ is the pressure (in bar) of the gas Z at temperature T and p° = 1 bar. (Given, d(ln K)/d(1/T) = −ΔH°/R, where the equilibrium constant, K = pZ/p° and the gas constant, R = 8.314 J K−1 mol−1) The value of ΔS° (in J K−1 mol−1) for the given reaction, at 1000 K is ___.

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