A4 Find the resistivity of the gas at sufficiently small values of the... · OlympiadBench #1118

Physics · electromagnetism

Problem

A4 Find the resistivity ρgas\rho_{gas} of the gas at sufficiently small values of the voltage applied and express it in terms of β,L,Zext,r\beta,L,Z_{ext},r and ee Given constants: Problem3. Simplest model of gas discharge An electric current flowing through a gas is called a gas discharge. There are many types of gas discharges including glow discharge in lighting lamps, arc discharge inwelding and the well known spark discharge that occurs between the clouds and the earth in the form of lightning. Part A. Non-self-sustained gas discharge In this part of the problem the so-called non-self-sustained gas discharge is studied. To maintain it a permanent operationan external ionizer is needed, which creates Zext Z_{\text {ext }} pairs of singly ionized ions and free electrons per unit volume and per unit time uniformly in the volume. When an external ionizer is switched on, the number of electrons and ions starts to grow. Unlimited increase in the number densities of electrons and ions in the gas is prevented by the recombination process in which a free electron recombineswith an ion to form a neutral atom. The number of recombining events Zrec Z_{\text {rec }} that occurs in the gas per unit volume and per unit time is given by Zrec=rneni,Z_{\mathrm{rec}}=r n_{e} n_{i}, where rr is a constant called the recombination coefficient, and ne,nin_{e}, n_{i} denotethe electron and ion number densities, respectively. Suppose that at time t=0t=0 the external ionizer is switched on and the initial number densities of electrons and ions in the gas are both equal to zero. Then, the electron number density ne(t)n_{e}(t) depends on timetas follows: ne(t)=n0+atanh⁡btn_{e}(t)=n_{0}+a \tanh b t where n0,an_{0}, a and bb are some constants, and tanh⁡x\tanh x stands for the hyperbolic tangent. Context question: A1 Find 0,a,b_{0}, a, b and express them in terms of Zext Z_{\text {ext }} and rr. Context answer: n0=0n_{0}=0 , a=Zextra=\sqrt{\frac{Z_{e x t}}{r}} , b=rZextb=\sqrt{r Z_{e x t}} Extra Supplementary Reading Materials: Assume that there are two external ionizers available. When the first one is switched on, the electron number density in the gas reaches its equilibrium value of be ne1=12⋅1010 cm−3n_{e 1}=12 \cdot 10^{10} \mathrm{~cm}^{-3}. When the second external ionizer is switched on, the electron number density reaches its equilibrium value of ne2=16n_{e 2}=16. 1010 cm−310^{10} \mathrm{~cm}^{-3}. Context question: A2 Find the electron number density nen_{e} at equilibrium when both external ionizers are switched on simultaneously. Context answer: 20.0⋅101020.0 \cdot 10^{10} Extra Supplementary Reading Materials: Attention!In what follows it is assumed that the external ionizer is switched on for quite long period of time such that all processes have become stationary and do not depend on time. Completely neglect the electric field due the charge carriers. Assume that the gas fills in the tube between the two parallel conductive plates of area SS separated by the distance L≪SL \ll \sqrt{S} from each other. The voltage UU is applied across the plates to create an electric field between them. Assume that the number densities of both kinds of charge carriers remain almost constant along the tube. Assumethat both the electrons (denoted by thesubscripte) and the ions (denoted by the subscripti) acquire the same ordered speed vv due to the electric field strength EE found as v=βEv=\beta E where bisa constant called charge mobility. Context question: A3 Express the electric current II in the tube in terms of U,β,L,S,Zext,rU, \beta, L, S, Z_{\mathrm{ext}}, r and ee which is the elementary charge. Context answer: I=eβ2U2SrL3(1+4rZextL4β2U2−1)I=\frac{e \beta^{2} U^{2} S}{r L^{3}}(\sqrt{1+\frac{4 r Z_{e x t} L^{4}}{\beta^{2} U^{2}}}-1)

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