A piecewise function p is defined on the closed interval [−2,6] by
p(x)={2x+5,kln(x+2),−2≤x<1,1≤x≤6,
where k is a nonzero real constant.
The natural logarithm is defined only for positive arguments, so x+2>0 must hold wherever the logarithmic expression is used.
a. Part 1: (a) State the largest possible domain of p within [−2,6] without imposing any additional conditions on k. Briefly justify your answer referring to the restrictions of the component functions.
b. Part 2: (b) Determine the value of k that makes p continuous on the entire interval [−2,6]. Show all limit evaluations and algebraic manipulations.
c. Part 3: (c) Using the value of k from part (b), evaluate ∫−26p(x)dx. Explain why the integral is guaranteed to exist based on the continuity of p.