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Mathematics
Problem
∫
(
x
+
2
x
+
4
)
2
e
x
d
x
\int \left(\frac{x+2}{x+4}\right)^2 e^x\,dx
∫
(
x
+
4
x
+
2
)
2
e
x
d
x
is equal to (a)
e
x
(
x
x
+
4
)
+
c
e^x\left(\frac{x}{x+4}\right) + c
e
x
(
x
+
4
x
)
+
c
(b)
e
x
(
x
+
2
x
+
4
)
+
c
e^x\left(\frac{x+2}{x+4}\right) + c
e
x
(
x
+
4
x
+
2
)
+
c
(c)
e
x
(
x
−
2
x
+
4
)
+
c
e^x\left(\frac{x-2}{x+4}\right) + c
e
x
(
x
+
4
x
−
2
)
+
c
(d)
(
2
x
e
2
x
+
4
)
+
c
\left(\frac{2xe^2}{x+4}\right) + c
(
x
+
4
2
x
e
2
)
+
c
(a)
e
x
(
x
x
+
4
)
+
c
e^x\left(\frac{x}{x+4}\right) + c
e
x
(
x
+
4
x
)
+
c
(b)
e
x
(
x
+
2
x
+
4
)
+
c
e^x\left(\frac{x+2}{x+4}\right) + c
e
x
(
x
+
4
x
+
2
)
+
c
(c)
e
x
(
x
−
2
x
+
4
)
+
c
e^x\left(\frac{x-2}{x+4}\right) + c
e
x
(
x
+
4
x
−
2
)
+
c
(d)
(
2
x
e
2
x
+
4
)
+
c
\left(\frac{2xe^2}{x+4}\right) + c
(
x
+
4
2
x
e
2
)
+
c
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