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Mathematics
Problem
If
f
(
x
)
=
(
x
−
x
0
)
g
(
x
)
f(x) = (x - x_0)g(x)
f
(
x
)
=
(
x
−
x
0
)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is continuous at
x
0
x_0
x
0
, then
f
′
(
x
0
)
f'(x_0)
f
′
(
x
0
)
is equal to (a) 0 (b)
x
0
x_0
x
0
(c)
g
(
x
0
)
g(x_0)
g
(
x
0
)
(d) None of these
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