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Chemistry
Problem Calculate the equivalent mass of each oxidant and reductant in:
a. FeSO 4 + KClO 3 ⟶ KCl + Fe 2 ( SO 4 ) 3 \text{FeSO}_4 + \text{KClO}_3 \longrightarrow \text{KCl} + \text{Fe}_2(\text{SO}_4)_3 FeSO 4 + KClO 3 ⟶ KCl + Fe 2 ( SO 4 ) 3 Na 2 SO 3 + Na 2 CrO 4 ⟶ Na 2 SO 4 + Cr ( OH ) 3 \text{Na}_2\text{SO}_3 + \text{Na}_2\text{CrO}_4 \longrightarrow \text{Na}_2\text{SO}_4 + \text{Cr}(\text{OH})_3 Na 2 SO 3 + Na 2 CrO 4 ⟶ Na 2 SO 4 + Cr ( OH ) 3 Fe 3 O 4 + KMnO 4 ⟶ Fe 2 O 3 + MnO 2 \text{Fe}_3\text{O}_4 + \text{KMnO}_4 \longrightarrow \text{Fe}_2\text{O}_3 + \text{MnO}_2 Fe 3 O 4 + KMnO 4 ⟶ Fe 2 O 3 + MnO 2 KI + K 2 Cr 2 O 7 ⟶ Cr 3 + + 3 I 2 \text{KI} + \text{K}_2\text{Cr}_2\text{O}_7 \longrightarrow \text{Cr}^{3+} + 3\text{I}_2 KI + K 2 Cr 2 O 7 ⟶ Cr 3 + + 3 I 2 Mn 4 + ⟶ Mn 2 + \text{Mn}^{4+} \longrightarrow \text{Mn}^{2+} Mn 4 + ⟶ Mn 2 + NO 3 − ⟶ N 2 \text{NO}_3^- \longrightarrow \text{N}_2 NO 3 − ⟶ N 2 N 2 ⟶ NH 3 \text{N}_2 \longrightarrow \text{NH}_3 N 2 ⟶ NH 3 Na 2 S 2 O 3 + I 2 ⟶ Na 2 S 4 O 6 + 2 NaI \text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \longrightarrow \text{Na}_2\text{S}_4\text{O}_6 + 2\text{NaI} Na 2 S 2 O 3 + I 2 ⟶ Na 2 S 4 O 6 + 2 NaI FeC 2 O 4 ⟶ Fe 3 + + CO 2 \text{FeC}_2\text{O}_4 \longrightarrow \text{Fe}^{3+} + \text{CO}_2 FeC 2 O 4 ⟶ Fe 3 + + CO 2 Browse the problem library