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Mathematics
Mathematics
Problem
Which of the following integrals correctly represents the area enclosed by the polar curve
r
=
3
sin
θ
r = 3\sin\theta
r
=
3
sin
θ
for
0
≤
θ
≤
π
0 \le \theta \le \pi
0
≤
θ
≤
π
? a)
∫
0
π
(
3
sin
θ
)
2
d
θ
\displaystyle \int_{0}^{\pi} (3\sin\theta)^2\, d\theta
∫
0
π
(
3
sin
θ
)
2
d
θ
b)
1
2
∫
0
π
3
sin
θ
d
θ
\displaystyle \tfrac12 \int_{0}^{\pi} 3\sin\theta\, d\theta
2
1
∫
0
π
3
sin
θ
d
θ
c)
1
2
∫
0
π
(
3
sin
θ
)
2
d
θ
\displaystyle \tfrac12 \int_{0}^{\pi} (3\sin\theta)^2\, d\theta
2
1
∫
0
π
(
3
sin
θ
)
2
d
θ
d)
1
2
∫
0
π
/
2
(
3
sin
θ
)
2
d
θ
\displaystyle \tfrac12 \int_{0}^{\pi/2} (3\sin\theta)^2\, d\theta
2
1
∫
0
π
/2
(
3
sin
θ
)
2
d
θ
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