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Mathematics
Mathematics
Problem
The position of a particle as a function of time
t
t
t
, is given by
x
(
t
)
=
a
t
+
b
t
2
−
c
t
3
x(t) = at + bt^2 - ct^3
x
(
t
)
=
a
t
+
b
t
2
−
c
t
3
where,
a
,
b
a, b
a
,
b
and
c
c
c
are constants. When the particle attains zero acceleration, then its velocity will be: a.
a
+
b
2
4
c
a + \frac{b^2}{4c}
a
+
4
c
b
2
b.
a
+
b
2
3
c
a + \frac{b^2}{3c}
a
+
3
c
b
2
c.
a
+
b
2
c
a + \frac{b^2}{c}
a
+
c
b
2
d.
a
+
b
2
2
c
a + \frac{b^2}{2c}
a
+
2
c
b
2
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