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Mathematics
Mathematics
Problem
The equation of the diameter of the circle
3
(
x
2
+
y
2
)
−
2
x
+
6
y
−
9
=
0
3(x^2 + y^2) - 2x + 6y - 9 = 0
3
(
x
2
+
y
2
)
−
2
x
+
6
y
−
9
=
0
which is perpendicular to the line
2
x
+
3
y
=
12
2x + 3y = 12
2
x
+
3
y
=
12
is a.
3
x
−
2
y
+
3
=
0
3x - 2y + 3 = 0
3
x
−
2
y
+
3
=
0
b.
3
x
−
2
y
−
3
=
0
3x - 2y - 3 = 0
3
x
−
2
y
−
3
=
0
c.
3
x
−
2
y
+
1
=
0
3x - 2y + 1 = 0
3
x
−
2
y
+
1
=
0
d.
3
x
−
2
y
−
1
=
0
3x - 2y - 1 = 0
3
x
−
2
y
−
1
=
0
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