Mathematics

Mathematics

Problem

If a=4i^+6j^\mathbf{a} = 4\hat{i} + 6\hat{j} and b=3j^+4k^\mathbf{b} = 3\hat{j} + 4\hat{k} , then the component of a\mathbf{a} along b\mathbf{b} is a. 18103(3j^+4k^)\frac{18}{10\sqrt{3}}(3\hat{j} + 4\hat{k}) b. 1825(3j^+4k^)\frac{18}{25}(3\hat{j} + 4\hat{k}) c. 183(3j^+4k^)\frac{18}{\sqrt{3}}(3\hat{j} + 4\hat{k}) d. (3j^+4k^)(3\hat{j} + 4\hat{k})

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