Physics

Physics

Problem

The motion of a particle is described by the equation d2xdt2+16x=0\dfrac{d^{2}x}{dt^{2}} + 16x = 0. If this motion corresponds to small oscillations of a simple pendulum on Earth where g=9.8 m s−2g = 9.8\,\text{m}\,\text{s}^{-2}, find the length LL of the pendulum. a) 1.6 m1.6\,\text{m} b) 0.31 m0.31\,\text{m} c) 0.61 m0.61\,\text{m} d) 2.45 m2.45\,\text{m}

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