1.∫(x3+3x2+3x+1)(x+1)5dx=1. \int \frac{(x^3 + 3x^2 + 3x + 1)}{(x+1)^5} dx =

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1.∫(x3+3x2+3x+1)(x+1)5dx=1. \int \frac{(x^3 + 3x^2 + 3x + 1)}{(x+1)^5} dx =

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