Physics

Problem

A block starts from rest at the top of a smooth track

16\,\text{m}

above the ground. At a point

4\,\text{m}

above the ground its speed is

v

. The block continues to move and climbs the opposite side of the track. At what height above the ground will its speed become

\dfrac{v}{2}

? Take

g = 10\,\text{m/s}^2

. a)

10\text{ m}

16\text{ m}

13\text{ m}

14\text{ m}