Mathematics

Mathematics

Problem

Suppose dydx=ycos⁡x\displaystyle \frac{dy}{dx}=y\cos x with y ⁣(π2)=1y\!\left(\tfrac{\pi}{2}\right)=1. A student begins at x=π2x=\tfrac{\pi}{2} and advances in equal increments of Δx=π6\Delta x=\tfrac{\pi}{6}, updating yy at each step. After three such increments, what is the student’s approximation to y(π)y(\pi)? a) 0.5450.545 b) 0.4040.404 c) 0.7380.738 d) 0.6090.609

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