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Mathematics
Mathematics
Problem
Suppose
d
y
d
x
=
y
cos
x
\displaystyle \frac{dy}{dx}=y\cos x
d
x
d
y
=
y
cos
x
with
y
(
π
2
)
=
1
y\!\left(\tfrac{\pi}{2}\right)=1
y
(
2
π
)
=
1
. A student begins at
x
=
π
2
x=\tfrac{\pi}{2}
x
=
2
π
and advances in equal increments of
Δ
x
=
π
6
\Delta x=\tfrac{\pi}{6}
Δ
x
=
6
π
, updating
y
y
y
at each step. After three such increments, what is the student’s approximation to
y
(
π
)
y(\pi)
y
(
π
)
? a)
0.545
0.545
0.545
b)
0.404
0.404
0.404
c)
0.738
0.738
0.738
d)
0.609
0.609
0.609
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