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Mathematics
Mathematics
Problem
If
log
x
+
log
y
=
log
(
x
+
y
)
\log x + \log y = \log(x + y)
lo
g
x
+
lo
g
y
=
lo
g
(
x
+
y
)
and
y
=
f
(
x
)
y = f(x)
y
=
f
(
x
)
, then
y
=
y =
y
=
(a)
x
x
−
1
\frac{x}{x-1}
x
−
1
x
(b)
x
x
+
1
\frac{x}{x+1}
x
+
1
x
(c)
x
−
1
x
\frac{x-1}{x}
x
x
−
1
(d)
x
+
1
x
−
1
\frac{x+1}{x-1}
x
−
1
x
+
1
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