JEE Advanced 2012 Paper 1 Physics Q20

Physics · Dual Nature of Radiation & Matter · Electrostatic Potential & Capacitance

Problem

A proton is fired from very far away towards a nucleus with charge Q=120eQ=120e, where ee is the electronic charge. It makes a closest approach of 10 fm10\,\mathrm{fm} to the nucleus. The de Broglie wavelength (in units of fm) of the proton at its start is: (take the proton mass, mp=(5/3)×10−27 kgm_p=(5/3)\times10^{-27}\,\mathrm{kg}; h/e=4.2×10−15 J s/Ch/e=4.2\times10^{-15}\,\mathrm{J\,s/C}; 1/(4πε0)=9×109 m/F1/(4\pi\varepsilon_0)=9\times10^9\,\mathrm{m/F}; 1 fm=10−15 m1\,\mathrm{fm}=10^{-15}\,\mathrm m)

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